Question

solve by factor method3(3x-1/2x+3)-2(2x+3/3x-1)=5​

Answer 1

Answer:

x = 0, 4

Step-by-step explanation:

$3( \frac{3 x - 1}{2x + 3} ) - 2( \frac{2x + 3}{3x - 1} ) = 5 \\ or \: 3m- \frac{2}{m} =5 \\ or \: 3 {m}^{2} - 2 = 5m \\ or \: 3 {m}^{2} - 5m - 2 = 0 \\ or \: 3 {m}^{2} - 6m + m - 2 = 0 \\ or \: (m - 2)(3m + 1) = 0 \\ or \: m - 1 = 0 \\ or \: m = 1 \\or \: \frac{3x - 1}{2x + 3} = 1 \\ or \: 3x - 1 = 2x + 3 \\ or \: x = 4 \\ \\ and \:3m + 1 = 0 \\ or \: m = - \frac{1}{3} \\ or \: \frac{3x - 1}{2x + 3} = - \frac{1}{3} \\ or \: 9x - 3 = - 2x - 3 \\ or \: 11x = 0 \\ or \: x = 0$

$here \: m = \frac{3x - 1}{2x + 3}$