Question

solve by factorisation 2x^2 -2x +1\8

Answer 1

hay!!

Dear user -

$2 {x}^{2} - 2x + \frac{1}{8} \\ \frac{16 {x}^{2} - 16x + 1}{8} \\ 16 {x}^{2} - 16x + 1 = 8 \\ 16 {x}^{2} - 16x - 7 = 0$
I hope it's help you