Question

Solve by factorisation
2x^2+3x-20=0

Answer 1

Step-by-step explanation:

2x^2+3x-20=0

2x^2+8x-5x-20=0

2x(x+4)-5(x+4)=0

(2x-5)(x+4)=0

x=-4 or 5/2

Answer 2

Answer:

2×^2+3×-20=0

(2)^2×3×-20=0

4×3×-20=0

12×-20=0

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