Question

solve by factorisation
2x^2+3x-20=0​

Answer 1

Answer:

Reffer the attachment for your answer mate

Answer 2

$\star\underline{\mathtt\orange{⫷❥Q᭄} \mathfrak\blue{u~ }\mathfrak\blue{Σ} \mathbb\purple{ §}\mathtt\orange{T} \mathbb?\pink{iOn⫸}}\star\:$

2x²+3x-20=0

${ \color{aqua}{ \underbrace{ \underline{ \color{lime}{ \mathbb{✯꧁ ⋆᭄ SoLuTiOn⋆᭄꧂✯ }}}}}}$

$2x²+3x-20=0$

$multiply \: first \: and \: last \: terms$

$= - 40 {x}^{2} \\ factors = + 8x - 5x$

$2x²+8x-5x-20=0$

$2x(x+4)-5(x+4)=0$

$(x+4)(2x-5)=0$

$x+4=0\:or\:2x-5=0$

$x=-4\:or\:2x=5$

$x=-4\:or\:x=\frac{5}{2}$

$x=-4\:or\:x=2.5$

$\blue{\boxed{\blue{ \bold{\fcolorbox{red}{black}{\green{☺︎︎Hope\:It\:Helps☺︎︎}}}}}}$

${\mathbb{\colorbox {orange} {\boxed{\boxed{\boxed{\boxed{\boxed{\colorbox {lime} {\boxed{\boxed{\boxed{\boxed{\boxed{\colorbox {aqua} {@suraj5069}}}}}}}}}}}}}}}$