Question

solve by factorisation
2x^2+3x-20=0​

Answer 1

Step-by-step explanation:

2x²+8x-5x-20

2x(x+4) -5(x+4)

(x+4) (2x-5 )

x= -4 , 5/2

Answer 2

Answer:

(x+4)(2x-5)

Step-by-step explanation:

The factors of 40x² is 8x & 5x, the difference of 8x & 5x is 3x

Solution:

$\implies$ $\sf{2x^2 + 8x - 5x - 20 }$

$\implies$ $\sf{2x(x + 4) -5(x+4) }$

$\implies$ $\sf{(x+4) (2x - 5) }$

$\therefore$ $\boxed{\sf{ x = -4\ or\ x = {\frac{5}{2}} }}$

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