Question

solve by factorisation 2x^2-x-3​

Answer 1

Answer:

$2x ^{2} - x - 3 \\ \\ 2x ^{2} + 2x - 3x - 3 \\ \\ 2x(x - 1) \: - 3(x + 1) \\ \\ (x - 1)(2x - 3) \\ \\ x = 1 \: \: x = \frac{3}{2}$

Answer 2

Answer:

(x+1)(2x-3)

Step-by-step explanation:

$2x^{2} -x-3\\2x^{2} +2x-3x-3\\2x(x+1)-3(x+1)\\(x+1)(2x-3)$(product of 2*-3 = -6  and sum of 2-3= -1 .That's why we have taken 2x and -3x (according to middle splitting))