solve by factorisation a²x²-(a²b²+1)x+b²
Answers
Answered by
6
Answer:
Step-by-step explanation:
=−a2b2x+a2x2+b2−x
Answered by
8
Answer:
a²b²x² – (a² - b²) x + 1 = 0
Solution:
a²b²x² – (a² - b²) x + 1 = 0
a²b²x² – a² x - b² x + 1 = 0
a²x (b² x – 1) -1(b² x – 1) = 0
(b² x – 1) (a² x – 1) = 0
(b² x – 1) = 0 (a² x – 1) = 0
b² x = 1 a² x = 1
x =1/b² x = 1/a²
Verification:
a²b²x² – (a² - b²) x + 1 = 0
if x = 1/a²
a²b²(1/a²)² – (a² - b²) (1/a²) + 1 = 0
b²/a² - a²/a² + b²/a² + 1 = 0
- 1 + 1 = 0
0 = 0
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