Question

solve by factorisation method :-
1. 4(2x-3)^2 -(2x-3) -14=0​

Answer 1

$let \: (2x - 3) = y \\ \\ 4 {y}^{2} - y - 14 = 0 \\ \\ 4 {y}^{2} - 8y + 7y - 14 = 0 \\ \\ 4y(y - 2) + 7(y - 2) = 0 \\ \\ (y - 2)(4y + 7) = 0 \\ \\ y = 2 \: \: \: or \: \: \: - \frac{7}{4} \\ \\ \\ 2x - 3 = 2 \\ \\ 2x = 5 \\ \\ x = \frac{5}{2}$

Answer 2

Step-by-step explanation:

this is your answer my friend

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