Math, asked by Anonymous, 10 months ago

Solve by factorisation method :
1/x+1 +1/x+3=1/ x+2+1/x+4=(x#-1,-2, -4,-3)​

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Answered by Anonymous
2

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We have, x2/3 + x1/3 - 2 = 0 Let x1/3 = y then, x2/3 + x1/3 - 2 = 0 y2 + y - 2 = 0 y2 + (2 - 1)y - 2 = 0 y2 + 2y - 1y - 2 = 0 y(y + 2) - 1(y + 2) = 0 (y ...

We have, x2/3 + x1/3 - 2 = 0 Let x1/3 = y then, x2/3 + x1/3 - 2 = 0 y2 + y - 2 = 0 y2 + (2 - 1)y - 2 = 0 y2 + 2y - 1y - 2 = 0 y(y + 2) - 1(y + 2) = 0 (y ...

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