Math, asked by iampinku02, 8 months ago

solve by factorisation method ​

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Answered by PhysicsForever
1

Answer:

x^2-x-132 = 0

Clearly, the factors of 132 are 12 and 11 such that also, their difference is 1

So,

x^2-x-132 = x^2-12x+11x-132 = 0

x(x-12)+11(x-12) = 0

(x-12)(x+11) = 0

So,

x= -11 or 12.

Answered by Anonymous
4

Answer:

x²-12x+11x-132

x(x-12)+11(x-12)

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