Question

solve by factorisation method 2x square +5x+2=0​

Answer 1

Answer:

Given,

x22−x5+2=0

2−5x+2x2=0

2x2−5x+2=0

(x−2)(2x−1)=0

x=2,21

Given,

x1−x−21=3

x−2−x=3(x)(x−2)

−2=3x2−6x

3x2−6x+2=0

x=2⋅3−(−6)±(−6)2−4⋅3⋅2

=66±12

=62(3±3)

x=33±3