Math, asked by Anonymous, 1 year ago

solve by factorisation method 8x^2 - 22x - 21 = 0

Answers

Answered by sushant2505
110
8x²-22x-21 = 0
8x²-28x+6x-21 = 0
4x(2x-7)+3(2x-7) = 0
(4x+3)(2x-7) = 0
x = -3/4 , 7/2
Answered by wifilethbridge
31

Answer:

x=\frac{-3}{4},x=\frac{7}{2}

Step-by-step explanation:

Given : 8x^2 - 22x - 21 = 0

To Find:solve by factorisation method

Solution:

8x^2 - 22x - 21 = 0

8x^2 - 28x+6x - 21 = 0

4x(2x - 7)+3(2x - 7) = 0

(4x+3)(2x - 7) = 0

(4x+3)=0,(2x - 7) = 0

x=\frac{-3}{4},x=\frac{7}{2}

Hence  x=\frac{-3}{4},x=\frac{7}{2}

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