Math, asked by 2016shaikhhanzlah10c, 2 months ago

solve by factorisation method
3x {}^{2}  - 2 \sqrt{6x}  + 2 = 0

Answers

Answered by gopalpvr
1

Answer:

X= √2/√3

Step-by-step explanation:

3x2-2√6x + 2=0

3x^2- √6x - √6x + 2 = 0

√3x(√3x-√2) -√2(√3x - √2) =0

(√3x-√2) (√3x-√2) =0

(√3x-√2) ^2=0

(√3x-√2) =0

X= √2/√3

or

(3x)^2-2(3)(2) x + (2)^2=0

(√3x-√2) ^2=0

√3x=2

X = 2/3

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