Question

solve by factorisation method
$3x {}^{2} - 2 \sqrt{6x} + 2 = 0$
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Answer 1

Answer:

X= √2/√3

Step-by-step explanation:

3x2-2√6x + 2=0

3x^2- √6x - √6x + 2 = 0

√3x(√3x-√2) -√2(√3x - √2) =0

(√3x-√2) (√3x-√2) =0

(√3x-√2) ^2=0

(√3x-√2) =0

X= √2/√3

or

(√3x)^2-2(√3)(√2) x + (√2)^2=0

(√3x-√2) ^2=0

√3x=√2

X = √2/√3