Question

solve by factorisation method x^2+x-(a+1)(a+2)=0 x^2+3x-(a^2+a-2)=0

Answer 1

x 2 + x - (a + 1)(a + 2) = 0

⇒ x 2 + (a + 2 - a - 1)x - (a + 1)(a + 2) = 0

⇒ x 2 + (a + 2)x - (a + 1)x - (a + 1)(a + 2) = 0

⇒ x(x + (a + 2)) - (a + 1)(x + (a + 2)) = 0

⇒ (x - (a + 1))(x + (a + 2)) = 0

⇒ x = a + 1, x = -(a + 2)

x2+3x-(a2+a-2)=0

x2+x-(a+1)(a+2)=0

4/x-5/2x+3=3

(x+3)/(x-2)-(x-1)/x=17/4

5x2-6x-2=0