Math, asked by sunainaillur, 2 months ago

solve by Factorisation
x2 + 5 x + 6 =0​

Answers

Answered by pawaskarmishti
1

Answer:

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Step-by-step explanation:

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Attachments:
Answered by siddhi5229
2

Answer:

Use the quadratic formula

=

±

2

4

2

x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}

x=2a−b±b2−4ac

Once in standard form, identify a, b and c from the original equation and plug them into the quadratic formula.

2

+

5

+

6

=

0

x^{2}+5x+6=0

x2+5x+6=0

=

1

a={\color{#c92786}{1}}

a=1

=

5

b={\color{#e8710a}{5}}

b=5

=

6

c={\color{#129eaf}{6}}

c=6

=

5

±

5

2

4

1

6

2

1

x=\frac{-{\color{#e8710a}{5}} \pm \sqrt{{\color{#e8710a}{5}}^{2}-4 \cdot {\color{#c92786}{1}} \cdot {\color{#129eaf}{6}}}}{2 \cdot {\color{#c92786}{1}}}

x=2⋅1−5±52−4⋅1⋅6

2

Simplify

Evaluate the exponent

Multiply the numbers

Subtract the numbers

Evaluate the square root

Multiply the numbers

=

5

±

1

2

x=\frac{-5 \pm 1}{2}

x=2−5±1

3

Separate the equations

To solve for the unknown variable, separate into two equations: one with a plus and the other with a minus.

=

5

+

1

2

x=\frac{-5+1}{2}

x=2−5+1

=

5

1

2

x=\frac{-5-1}{2}

x=2−5−1

4

Solve

Rearrange and isolate the variable to find each solution

=−2

x=-2

x=−2

=−3

x=-3

x=−3

Solution

=−2

=−3

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