Question

solve by factorisation:

x2 +[a/a+b + a+b/a]x + 1 =0

Answer 1

Answer:

hiya... here's your answer

Answer 2

Given,

An algebraic equation: x^2 +[a/(a+b) + (a+b)/a]x + 1 = 0

To find,

To simplify and find the value of x that satisfies this equation, by factorization method.

Solution,

We can simply solve this mathematical problem using the following process:

On simplifying the given algebraic equation by using the factorization method, we get;

x^2 +[a/(a+b) + (a+b)/a]x + 1 = 0

=> x^2 +[a/(a+b)]x + [(a+b)/a]x + {a(a+b)/a(a+b)} = 0

=> x [x + a/(a+b)] + [(a+b)/a]×[x + a/(a+b)] = 0

{By using splitting the middle term formula}

=> [x + a/(a+b)]×[x + (a+b)/a] = 0

=> [x + a/(a+b)] = 0 or [x + (a+b)/a] = 0

=> x = -a/(a+b) or x = -(a+b)/a

Hence, the value of x that satisfies this equation is found to be -a/(a+b) and -(a+b)/a respectively, by the factorization method.