Question

solve by factorization 2x^2-x+1/8=0​

Answer 1

Answer:

∴ $x=\frac{1}{4}$ (Multiple Root)

Step-by-step explanation:

$2x^2-x+1/8=0$

$\frac{1}{8} (16x^2-8x+1)=0$

$\frac{1}{8} (4x-1)^2=0$

∴ $x=\frac{1}{4}$ (Multiple Root)