Question

solve by factorization : - 2x² + 9x + 9 = 0
guys please give correct ans i will Mark as a Brain list ans​

Answer 1

Step-by-step explanation:

2x² + 9x + 9 = 0

=>2x²+6x+3x+9=0

=>2x(x+3)+3(x+3)=0

=>(x+3)(2x+3)=0

=>x= -3 or -3/2.

Answer 2

Question:

• Solve by factorization : 2x² + 9x + 9 = 0

Solution:

$\longmapsto \sf 2x^2+9x+9=0$

Splitting middle term :

$\dasharrow \sf 2x^2 + 6x+3x+9=0$

Take common factor from each term :

$\dasharrow \sf 2x(x+3) + 3(x+3) =0$

Take (x+3) common from both terms :

$\dasharrow \sf (x+3)(2x+3) =0$

Equate :

$\bullet \sf{( x + 3) = 0 }\implies \sf \pink{x=-3}$

$\bullet \sf{( 2x + 3) = 0 }\implies \sf \pink{x=\frac{-3}{2}}$

Therefore,

• x = -3 or -3/2

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Verification:

• Putting x = -3

$\longmapsto \sf 2x^2+9x+9=0\\\\\implies 2(-3)^2+9(-3)+9\\\\\implies \sf2(9)-27+9 \\\\\implies 18-18\\\\\implies 0 (True)$

• Putting x = -3/2

$\longmapsto \sf 2x^2+9x+9=0\\\\\implies 2(\frac{-3}{2})^2+9(\frac{-3}{2})+9\\\\\implies \sf2(\frac{9}{4})-\frac{27}{2}+9 \\\\\implies \frac{9}{2}-\frac{27}{2}+9\\\\\implies 0 (True)$

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