Question

solve by factorization 3x^2-26x+40=0​

Answer 1

Answer:

roots of given equation are 2 and 20/3

Step-by-step explanation:

3x^2-26x+40=0

3x^2-(6+20)x+40=0

3x^2 -6x-20x+40=0

3x(x-2)-20(x-2)=0

(3x-20)(x-2)=0

x=20/3 or x=2