Question

solve by factorization: a^2x^2-(a^2b^2+1)x+b^2=0​

Answer 1

Answer:

a2x2-a2b2x-x+b2

a2x(x-b2) -1 (x-b2)

(a2x-1)(x-b2)

by putting this equal to zero we can find the value of x