Question

solve by factorization method
10x^2 + 3bx+a^2-7ax-b^2 =0
​

Answer 1

Step-by-step explanation:

10x² + 3bx + a² - 7ax + b² = 0

=> 10x² + (3b - 7a)x + a² + b² = 0

Note that this is of the form of Ax² + Bx + C

Where A = 10 , B = (3b - 7z) , and C = (a² + b²)

So by using the standard Quadratic Formula:-  $x = \frac{-(3b - 7a) + \sqrt{(3b - 7a)^2- 4*10*(a^2 + b^2)}}{20}$ and $x = \frac{-(3b - 7a) - \sqrt{(3b - 7a)^2- 4*10*(a^2 + b^2)}}{20}$ .

You can calculate both the values of x and this is your answer.