Math, asked by dgadia87, 9 months ago

solve by factorization method

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Answered by swetarani402

1

Answer:

x²-3√3x+6=0

x²-2√3x-√3x+6=0

(x²-2√3x)(-√3x+6)=0

x(x-2√3)-√3(x-2√3)=0

(x-2√3)(x-√3)

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