Math, asked by choprasahil2004, 1 year ago

solve by factorization method 3root5x^2+25x+10root5=0

Answers

Answered by nskathait
42

Step-by-step explanation:

3root5x^2 +25x+ 10 root 5

product = ac= 3 √5x^2 X 10√5

= 150x^2

sum = 25x

no.s are = 15x , 10x

( 3√5x^2 + 15x) ( 10x + 10√5)

3√5x(X+ √5) +10( X + √5)

(3√5x + 10) ( X+ √5)

Answered by Anonymous
51

We have to solve the given quadratic equation by splitting the middle term

We have,

3√5x²+25x+10√5=0

To find the roots of the equation

By splitting the middle term,

→3√5x²+15x+10x+10√5=0

→3√5x(x+√5)+10(x+√5)=0

→(x+√5)(3√5x+10)=0

→x+√5=0 or 3√5x+10=0

→x= -√5 or -10/3√5

The roots are -√5 and -10/3√5

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