Question

solve by factorization method

Answer 1

[tex]2 {y}^{2} + 27y + 1 = 0 \\ \\2 {y}^{2} + 26y \times y + 13 = 0 \\ 2y(y + 13) + (y + 13) = 0 \\ (13 + y) \times( 2y + 1) = 0 \\ y = - 13 ,y = - 1÷2
Hope this will help you.

Answer 2

here is your answer by Sujeet yaduvanshi,

2y²+27y+13
2y²+26y+y+13
2y(y+13)+1(y+13)
(2y+1)(y+13)


that's all praju dear.......