Question

solve by factorization method:9m²-16=0​

Answer 1

Answer:

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Answer 2

$9 {m}^{2} - 16 = 0$

$(3m) ^{2} - ( {4})^{2} = 0$

Now we know that,

${x}^{2} - {y}^{2} = (x + y)(x - y)$

$(3m + 4)(3m - 4) = 0$

now ,

$3m + 4 = 0 \: \: \: or \: \: \: 3m - 4 = 0$

$3m = - 4 \: \: \: \: or \: \: \: 3m = 4$

$m = \frac{ - 4}{3} \: \: or \: m = \frac{4}{3}$

Hope it helps you dear!!!..