Math, asked by shubham4888, 9 months ago

solve by factorization method.

ad²x(ax/b+2c/d)+c²b=0​

Answers

Answered by tonystark7549
7

Answer:

x = -1

Step-by-step explanation:

answer:

ad²x(ax/b + 2c/d) + c²b = 0

ad²x([adx + 2bc]/bd) = - bc² Cancel d on the left side

adx([adx + 2bc]/b) = - bc²

(adx)² + 2abcdx = - (bc)²

(adx)² + abcdx = - (bc)² + (bc)²

(x + 1)² = 0

x + 1 = 0

x = - 1

Answered by dydeepshikha04aug
2

Answer:

x= {(-b)÷ad}

Step-by-step explanation:

see the attachment

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