Question

Solve by factorization method :( m) 2 - 25 =0​

Answer 1

Step-by-step explanation:

m²-25=0

m²-5²=0

formula ➡️ a²-b² = (a+b)(a-b)

(m+5)(m-5)=0

1. m-5 = 0

m = 5

2. m+5 =0

m = -5

Thank you✌

Answer 2

Answer:

Required solution of the given equation is $m = \pm5$

Step-by-step explanation:

Given,

${m}^{2} - 25 = 0$

We want to solve this problem by factorization method.

We know,

${x}^{2} - {y}^{2} = (x + y)(x - y)$

So,

${m}^{2} - {5}^{2} = 0 \\ (m + 5)(m - 5) = 0$

If product of two terms is equal to zero then they are separately zero.

So,

$m + 5 = 0 \\ m = - 5$

and

$m - 5 = 0 \\ m = 5$

Required value of m is $\pm5$

Equation solving is a problem of Algebra.

Some important Algebra formulas:

${(x + y)}^{2} = {x}^{2} + 2xy + {y}^{2} \\ {(x - y)}^{2} = {x}^{2} - 2xy + {y}^{2} \\ {(x + y)}^{3} = {x}^{3} + 3 {x}^{2} y + 3x {y}^{2} + {y}^{3} \\ {(x - y)}^{3} = {x}^{3} - 3 {x}^{2} y + 3x {y}^{2} - {y}^{3} \\ {x}^{3} + {y}^{3} = {(x + y)}^{3} - 3xy(x + y) \\ {x}^{3} - {y}^{3} = {(x - y)}^{3} + 3xy(x - y) \\ {x}^{2} - {y}^{2} = (x + y)(x - y) \\ {x}^{2} + {y}^{2} = {(x - y)}^{2} + 2xy \\ {x}^{2} - {y}^{2} = {(x + y)}^{2} - 2xy \\ {x}^{3} - {y}^{3} = (x - y)( {x}^{2} + xy + {y}^{2} ) \\ {x}^{3} + {y}^{3} = (x - + y)( {x}^{2} - xy + {y}^{2} )$

Know more about Algebra,

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