Math, asked by krushna43722, 2 months ago

solve
by
formala methed: 3x²-5x+7=0​

Answers

Answered by dkhs
0

The roots (answers) are:

x

=

5

+

i

59

6

and,

x

=

5

i

59

6

Hence there are no real roots to this quadratic, which means it does not cross the x-axis.

Explanation:

3

x

2

5

x

+

7

=

0

is a quadratic equation. This can be solved in 3 ways: factorising, using the quadratic formula or by completing the square. It's not obvious how to factorise

3

x

2

5

x

+

7

=

0

so we'll use the quadratic formula:

x

=

b

±

b

2

4

a

c

2

a

a is the coefficient of

x

2

, in this case 3.

b is the coefficient of

x

, in this case -5.

c is the constant, in this case 7.

Putting these values into the quadratic equation:

x

=

(

5

)

±

(

5

)

2

4

(

3

)

(

7

)

2

(

3

)

x

=

5

±

25

84

6

x

=

5

±

59

6

x

=

5

±

i

59

6

So the roots are:

x

=

5

+

i

59

6

and,

x

=

5

i

59

6

59

is an imaginary number, equal to

1

59

, which equals

i

59

. The symbol for the square root of -1 is i. Thus the roots of this equation have a real part (the 5/6) and an imaginary part (the

±

i

59

6

). A number made up of a real and imaginary part is called a complex number. Hence there are no real roots to this quadratic, which means it does not cross the x-axis.

Answered by cooljamestherobioxga
0

Answer:

x= 5+√−59                                or          x= 5-√−59

      6                                                              6

Step-by-step explanation:

Formula Name:

Factorisation formula.

3x²-5x+7=0

Let's solve your equation step-by-step.

3x²−5x+7=0

For this equation: a=3, b=-5, c=7

3x²+−5x+7=0

Step 1: Use quadratic formula with a=3, b=-5, c=7.

x=  −b±√b2−4ac

       2a

Putting in values

x=  −(−5)±√(−5)2−4(3)(7)

               2(3)

x=  5±√−59

       6

x= 5+√−59                                or          x= 5-√−59

      6                                                              6

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