solve by formula method 2x*2+4x+1=0
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Answered by
1
Answer:
Step-by-step explanation:
b^2-4ac=4^2-4*2*1
=16-8
=8
x=-b+_root of b^2-4ac/2a
=-4+-root8/2*2
=-4+_2root2/4
=-4+2root2/4,-4-2root2/4
=2(-2+root2)/4,-2(2+root2)/4
-2+root2/2,-2-root2/2
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