Question

Solve by formula method (steps are required) :-
x²-3x-2=0

Answer 1

$\star\underline{\mathtt\orange{⫷❥Q᭄} \mathfrak\blue{u~ }\mathfrak\blue{Σ} \mathbb\purple{ §}\mathtt\orange{T} \mathbb?\pink{iOn⫸}}\star\:$

Solve by formula method (steps are required) :-

x²-3x-2=0

${ \color{aqua}{ \underbrace{ \underline{ \color{lime}{ \mathbb{✯꧁ ⋆᭄ SoLuTiOn⋆᭄꧂✯ }}}}}}$

${x}^{2} - 3x - 2 = 0$

$a = 1 \\ b = - 3 \\ c = - 2$

$formula \\ x = \frac{ - b± \sqrt{ {b}^{2} - 4ac } }{2a}$

$x = \frac{ - ( - 3)± \sqrt{ {( - 3)}^{2} - 4(1)( - 2) } }{2(1)}$

$x = \frac{3± \sqrt{9 + 8} }{2}$

$x = \frac{3± \sqrt{17} }{2}$

$x = \frac{3 + \sqrt{17} }{2} \: \: or \: \: x = \frac{3 - \sqrt{17} }{2}$

$\blue{\boxed{\blue{ \bold{\fcolorbox{red}{black}{\green{☺︎︎Hope\:It\:Helps☺︎︎}}}}}}$

${\mathbb{\colorbox {orange} {\boxed{\boxed{\boxed{\boxed{\boxed{\colorbox {lime} {\boxed{\boxed{\boxed{\boxed{\boxed{\colorbox {aqua} {@suraj5069}}}}}}}}}}}}}}}$

Answer 2

Answer:

Chandrasekhara Venkata Raman was an Indian physicist known mainly for his work in the field of light scattering. With his student K. S. Krishnan, he discovered that when light traverses a transparent material, some of the deflected light changes wavelength and amplitude