solve by formula method
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Given, 3x2+5x+2=0
On comparing this equation with ax2+bx+c=0, we get a=3,b=5 and c=2
Now, b2−4ac=(5)2−4×3×2
=25=24
=1
x=2a−b±b2−4ac
==2×3−5±1
=6−5±1
x=6−5+1
x=6−5−1
∴ 3−2 and −1 are the roots of the given quadratic equation.
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