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Solve by Gauss Seidel Method 2x+y+6z=9; 8x+3y+2z=13; x+5y+z=7​

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Answered by hardikchaudhary12
0

Answer:

Solve by Gauss Seidel Method 2x+y+6z=9; 8x+3y+2z=13; x+5y+z=7

Answered by itzcattie
4

Answer:

Convergence of Jacobi and Gauss-Seidel Method and Error

Reduction Factor

1HarpinderKaur,

2KhushpreetKaur

1,2Department of Mathematics Baba FaridCollege,Bathinda

Abstract: In this paper, it is shown that neither of the iterative methods always converges. That is, it is possible

to apply the Jacobi method or the Gauss-Seidel method to a system of linear equations and obtain a divergent

sequence of approximations. In such cases, it is said that the method diverges.So for convergence, the Diagonal

Dominance of the matrix is necessary condition before applying any iterative methods. Moreover, also

discussed about the error reduction factor in each iteration in Jacobi and Gauss-Seidel method.

Keywords: Jacobi Method, Gauss-Seidel Method, Convergence and Divergence, Diagonal Dominance,

Reduction of Error.

I. Introduction:

An iterative technique to solve an n×n linear system A =b starts with an initial approximation0

to the

solution ∗, and generates a sequence of vectors{x

(k)

}=0

that converges to ∗. Most of these iterative

techniques involve a process that converts the system A =b into an equivalent system of the form = S+

for some n×n matrix S and vector . After the initial vector 0

is selected, the sequence of approximate solution

vectors is generated by computing

(+1) =

() + , k=1,2,3,……The Jacobi method is based on solving for

every variable locally with respect to the other variables; one iteration corresponds to solving for every variable

once. It is easy to understand and implement, but convergence is slow.The Gauss-Seidel method is similar to the

Jacobimethodexceptthatit uses updated valuesassoonastheyareavailable. ItgenerallyconvergesfasterthantheJacobi

method, although still relatively slowly.

1.1 Jacobi Method:

The Jacobi method is a method of solving a matrix equation on a matrix that has no zeros along its

main diagonal. Each diagonal element is solved for, and an approximate value put in. The process is then

iterated until it converges.The Jacobi method is easily derived by examining each of the n equations in the linear

system of equations A =b . If in the i−th equation

=1 =

solve for the value of while assuming the

other entries of remain fixed. This gives

+1 =

1

− ≠

()

, i = 1,2, ... ,n. (i)

which is the Jacobi method. Note that thecomputation of

(+1)

requires each component in

()

except

()

.In this method, the order in which the equations are examined is irrelevant, since the Jacobi

method treats them independently.

The equation A =b, which is (L+D+U) =b, can be written asD = −(L+U) +b.This reduces to+1=-

−1

( + )+

−1

Fig. 1 : Splitting of matrix for Jacobi Method

Whe

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