Question

solve by identity 999^2

Answer 1

Hi friend!!!

We know that (x-y)²=x²+y²-2xy

Now, (999)²

=(1000-1)²

=(1000)²+1²-2(1000)(1)

=1000000+1-2000

=998001

I hope this will help you ;)

Answer 2

Heya ....☺


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Here's ur ans. ⬇

We can write 999 as 1000 - 1

So ,

${999}^{2} = {(1000 - 1)}^{2}$

$(a - b) {}^{2} = {a}^{2} - 2ab \: + {b}^{2}$

$(1000) {}^{2} - 2 \times 1 \times 1000 + 1$

$(1000) {}^{2} - 2000 + 1$

= 998001



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. ✌Hope it helps