solve by identity (a)- 103 ×107. (b)- 95×96
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-11021
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(a)- 103*107
=(100+3)²*(100*7)²
=(100²+3²+2*100*3)*(100²+7²+2*100*7)
=(10000+9+600)*(10000+49+1400)
=(10609)*(11409)
=10,93,68,181
(b)-95*96
=(100-5)²-(100-6)²
=(100²+5²-2*100*5)*(100²+6²-2*100*6)
=(10000+25-1000)*(10000+36-1200)
=(9025)*(8836)
=7,96,44,900
AAYA SAMAJ ME
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