Question

solve By Jyometrical method: 1+cot2theta = cosec2theta​

Answer 1

Firstly that's "geo"metrical not "Jyo".

Then

$\huge \tt To \: prove \:⇒$

$1 + {cot}^{2}0 = {cosec}^{2} 0$

$L.H.S = 1 + \frac{{cos}^{2}0}{ {sin}^{2} 0}$

$= \frac{ {sin}^{2}0 + {cos}^{2} 0}{ {sin}^{2}0 }$

$= \frac{1}{ {sin}^{2}0 } \: \: \: \: \: \: \: \: (∵ {sin}^{2} 0 + {cos}^{2}0 = 1 )$

$= {cosec}^{2} 0$

$R.H.S = {cosec}^{2} 0$

$hence, \: L.H.S=R.H.S$