solve by matrix method x-3y=5 5y -2x+9=0
Answers
Answered by
1
Answer:
[
4
3
−3
−5
][
x
y
]=[
3
7
]⇒AX=B⇒X=A
−1
B
A=[
4
3
−3
−5
]⇒∣A∣=4×5−3×−3=−11
=0
Adj.A=[
−5
−3
3
4
]
A
−1
=
∣A∣
1
Adj.A=
11
−1
[
−5
−3
3
4
]
X=A
−1
B⇒=
11
−1
[
−5
−3
3
4
][
3
7
]=
11
−1
[
6
19
]
[
x
y
]=[
−6/11
−19/11
]
⇒ x=
11
−6
and y=
11
−19
Step-by-step explanation:
please mark me Brenest answer
Answered by
0
Answer:
this is the answer east to solve
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