Question

Solve by matrix
x+y+z=6
x+2y+3z=14
x+4y+7z=30​

Answer 1

x + y + z = 6 ……(1) y + 2z = 8 ….(2) (2) ⇒ y = 8 – 2z ; (1) ⇒ x = 6 – y – z = 6 – (8 – 2z) – z = z – 2 Taking z = k, we get x = k – 2, y = 8 – 2k; k ∈ R Putting k = 1, we have one solution as x = – 1, y = 6, z =1.