Question

solve by process please​

Answer 1

please refer to the attachment...

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Answer 2

Answer:

(i) Solution =》

Let the number be x

$\frac{ - 8}{9} + x = 1 \\ = \frac{ - 8}{9} + \frac{x}{1} = 1 \\ \\ take \: the \: lcm \: of \: 9 \: and \: 1 = 9\\ \frac{ - 8 + 9x}{9} = 1 \\ = \frac{x}{9} = 1 \\ = x = 9 \times 1 \\ = x = 9 \\ \\ so \: the \: no \: is \: 9 \ \\ \\ \ (ii) \: solution \\ \\ let \: the \: no \: be \: x \\ \\ \frac{3}{15} - x = \frac{2}{27} \\ \frac{3}{15} - \frac{x}{1} = \frac{2}{27} \\ take \: the \: lcm \: of \: 15 \: and \: 1 = 15 \\ \\ \frac{3 - 15x}{15} = \frac{2}{27} \\ = \frac{ - 12x}{15} = \frac{2}{27} \\ = x = \frac{5}{54}$

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