Solve by quadratic formula 10xsq+ 7x + 6
Answers
Answered by
0
Answer:
cannot be solved
Step-by-step explanation:
the roots are imaginary
b^2-4ac
(7)^2-4(10)(6)
49-240
-191
Answered by
0
Answer:
cannot be solved because the value is negative so this is imaginary
Step-by-step explanation:
first we put abc
a=10
b=7
c=6
then we write quadratic formula
two formula's here
1. b^2-4ac
2.D= b+_ √b^2-4ac/2a
or
b±√b²-4ac/2a
after that use this Formula
1. (7)^2-4(10)(6)
= 49-240
= -191
roots are imaginary
2. 7±√7²-4(10)(6)/2(10)
= 7±√(49)-(240)/20
=7±√7(7)-5(3)(16)
= 7±7(4)√15
= 7±28√15
i 7+28√15
= 35√15
ii 7-28√15
= -21√15
this is your answer
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