Math, asked by 23445, 1 month ago

Solve by quadratic formula 10xsq+ 7x + 6

Answers

Answered by riteshaleti161
0

Answer:

cannot be solved

Step-by-step explanation:

the roots are imaginary

b^2-4ac

(7)^2-4(10)(6)

49-240

-191

Answered by cmathur940
0

Answer:

cannot be solved because the value is negative so this is imaginary

Step-by-step explanation:

first we put abc

a=10

b=7

c=6

then we write quadratic formula

two formula's here

1. b^2-4ac

2.D= b+_ √b^2-4ac/2a

or

b±√b²-4ac/2a

after that use this Formula

1. (7)^2-4(10)(6)

= 49-240

= -191

roots are imaginary

2. 7±√7²-4(10)(6)/2(10)

= 7±√(49)-(240)/20

=7±√7(7)-5(3)(16)

= 7±7(4)√15

= 7±28√15

i 7+28√15

= 35√15

ii 7-28√15

= -21√15

this is your answer

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