solve by quadratic formula
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Answer:
answer is 7 and -9
Step-by-step explanation:
1/(x-3) - 1/(x+5) = 1/6
[(x+5) - (x-3)]/[(x-3)(x+5)] = 1/6
[x+5-x+3]/[x²+5x-3x-15] = 1/6
8/[x² + 2x - 15] = 1/6
8 × 6 = x² + 2x - 15
48 = x² + 2x -15
x² + 2x - 15 - 48 = 0
x² + 2x - 63 = 0
x² + (9-7)x - 63 = 0
x² + 9x - 7x - 63 = 0
x(x + 9).-7(x + 9) = 0
(x - 7)(x + 9) = 0
x - 7 = 0 , x + 9 = 0
x = 7 and x = -9
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