Math, asked by bhupendra46, 1 year ago

solve by quadratic formula ​

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Answers

Answered by shivani3155
1

Answer:

answer is 7 and -9

Step-by-step explanation:

1/(x-3) - 1/(x+5) = 1/6

[(x+5) - (x-3)]/[(x-3)(x+5)] = 1/6

[x+5-x+3]/[x²+5x-3x-15] = 1/6

8/[x² + 2x - 15] = 1/6

8 × 6 = x² + 2x - 15

48 = x² + 2x -15

x² + 2x - 15 - 48 = 0

x² + 2x - 63 = 0

x² + (9-7)x - 63 = 0

x² + 9x - 7x - 63 = 0

x(x + 9).-7(x + 9) = 0

(x - 7)(x + 9) = 0

x - 7 = 0 , x + 9 = 0

x = 7 and x = -9

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