Question

solve by quadratic formula (2x+3)(3x-2)+2 =0​

Answer 1

I hope you understand......

Answer 2

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$(2x + 3)(3x - 2) + 2 = 0 \\ = > 6 {x}^{2} - 4x + 9x - 6 + 2 = 0 \\ = > 6 {x}^{2} + 5x - 4 = 0 \\ according \: to \: the \: equation \\ we \: can \: foll ow \: the \: equation \\ = a {x}^{2} + bx + c = 0 \\ here \: the \: coefficient \: of : {x}^{2} = 6 \\ the \: coefficient \: of : x = 5 \\ and \: \\ the \: coefficient \: of : c = - 4 \\ the \: formula \: of \: quadric \: equation \\ \\ is : x = \frac{ - b \frac{ + }{} \sqrt{ {b}^{2} - 4ac} }{2 \times a} \\ = > x = \frac{ - 5 \frac{ + }{} \sqrt{ {5}^{2} - 4 \times 6 \times ( - 4) } }{2 \times 6} \\ = > x = \frac{ - 5 \frac{ + }{} \sqrt{25 + 96} }{2 \times 6} \\ = > x = \frac{ - 5 \frac{ + }{} \sqrt{121} }{12} \\ = > x = \frac{ - 5 \frac{ + }{ } (11)}{12} \\ here \: we \: get \: two \: values \: like \\ x = \frac{ - 5 + 11}{12} = \frac{6}{12} = \frac{1}{2} \\ x = \frac{ - 5 - 11}{12} = \frac{ - 16}{12} = \frac{ - 4}{3}$

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✨✨✨hope it helps✨✨