Math, asked by himankdulhani, 8 months ago

solve by quadratic formula 3a^2 x^2+8abx+4b^2​

Answers

Answered by sanjaverma4243
0

Answer:

x=-2b/3a or -2b/a

Step-by-step explanation:

COMPARE 3a^2+8abx+ 4b^2=0 with

Ax^2+ bx+c=0 we get

A=3a^2 , B=8ab, c=4b^2

Discreminant

(d)= b^2- 4ac

=(8ab)^2- 4× (3a^2) (4b^2)

=64a^2b^2- 48 a^2 b^2

=16a^2b^2- -(1)

BY QUADRATIC FORMULA

x=-B+underroot D/2a

x=- 8ab+ underroot16a^2 b^2/ 2×3a^2

=- 8ab+ 4ab/ 6a^2

x=-8ab+ 4ab/ 6a^2 or -8ab - 4ab/6a^2

x=-4ab/ 6a^2 or -12ab/6a^2

x=-2b/3a or -2b/a

Similar questions