Solve by quadratic method x2-4x-5=0
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Answered by
6
Answer :-
• x² - 4x - 5
=> x² - 5x + x - 5
=> x (x - 5) + 1 (x - 5)
=> (x + 1) (x - 5)
=> x = - 1, 5
Answered by
0
Answer :-
• x² - 4x - 5
=> x² - 5x + x - 5
=> x (x - 5) + 1 (x - 5)
=> (x + 1) (x - 5)
=> x = - 1, 5
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