Question

solve by quartic formula 4x²-2x+¼=0​

Answer 1

Answer:

Step-by-step explanation:

4x^-2x-1=0

4x^2-2x-2x-1=0

2x(2x-1)-1(2x-1)=0

(2x-1)(2x-1)

(2x-1)^2

Answer 2

Answer:

The given quadratic is

$4x^{2} -2x+\frac{1}{4} =0\\\\16x^{2} -8x+1=0$

now use quadratic formula $x=\frac{-b+-\sqrt{b^{2} -4ac} }{2a}$

here $a=16,b=-8,c=1$

$x=\frac{8+-\sqrt{64-4*16*1} }{2*16}$

$x=\frac{8}{32} \\\\x=\frac{1}{4}$

hope this helps..