solve by rationalising the denominator
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Solution:
(7√3-5√2)/(√48+√18)
= (7√3-5√2)/(4√3+3√2)
=[(7√3-5√2)(4√3-3√2)]/[(4√3+3√2))(4√3-3√2)]
= (84-21√6-20√6+30)/[(4√3)²-(3√2)²]
= (114-41√6)/(48-18)
= (114-41√6)/30
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