Math, asked by sakshamprakash23, 11 months ago

solve by rationalising the denominator​

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Answers

Answered by mysticd
1

Solution:

(7√3-5√2)/(√48+√18)

= (7√3-5√2)/(4√3+3√2)

=[(7√3-5√2)(4√3-3√2)]/[(4√3+3√2))(4√3-3√2)]

= (84-21√6-20√6+30)/[(4√3)²-(3√2)²]

= (114-41√6)/(48-18)

= (114-41√6)/30

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