Question

solve by reduction them to a pair of linear equation 1÷4x+1÷3y=7÷12, 1÷x+2÷y=3​

Answer 1

Answer:

(1, 1)

Step-by-step explanation:

$\frac{1}{4x}$ + $\frac{1}{3y}$ = $\frac{7}{12}$

$\frac{1}{x}$ + $\frac{2}{y}$ = 3

Let

$\frac{1}{x}$ = a

$\frac{1}{y}$ = b

$\frac{1}{4}$ a + $\frac{1}{3}$ b = $\frac{7}{12}$ .............. (1)

a + 2b = 3 ............ (2)

12 × (1) - 2 × (2)

(3a - 2a) + (4b - 4b) = 7 - 6

a = 1 → (2)

1 + 2b = 3 ⇒ b = 1

$\frac{1}{x}$ = 1 ⇒ x = 1

$\frac{1}{y}$ = 1 ⇒ y = 1

(1, 1)