solve by simultanous 3a+5b=26;a+5b=22
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Multiply equation 2 by 3 and subtract the answer by equation 1...here it is see pic above
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3a+5b = 26. ( Equation 1)
1a+5b = 22. ( Equation 2)
(-). (-). (-). (By changing the signs)
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2a = 4
a = 4/2
a = 2
Substituting value of a in equation 1
Therefore
3a+5b=26
3(2)+5b=26
6 +5b=26
5b= 26-6
5b=20
b =20/5
b=4
Therefore the values of 'a' and 'b' are 2 and 4 respectively
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