Solve by splitting middle term
1) 5x^2 + 4√5x + 3
2) 2x^2 + 2√14x + 7
3) x^2 − √2x − 12
Answers
Answered by
1
Answer:
1) 5x² + 4√5x + 3
= 5x²+√5x+3√5x+3
= √5x(√5x+1)+3(√5x+1)
= (√5x+1)(√5x+3)
5x² + 4√5x + 3 = (√5x+1)(√5x+3)
x = -1/√5, -3/√5
2) 2x² + 2√14x + 7
= 2x²+√14x+√14x+7
= √2x(√2x+√7)+√7(√2x+√7)
= (√2x+√7)(√2x+√7)
2x² + 2√14x + 7 = (√2x+√7)(√2x+√7)
x = -√7/√5, -√7/√2
3) x²− √2x − 12
= x²+2√2x-3√2x-12
= x(x+2√2) - 3√2(x+2√2)
= (x-3√2)(x+2√2)
x²− √2x − 12 = (x-3√2)(x+2√2)
x = 3√2, -2√2
Similar questions