Math, asked by dhivakardhivakar, 3 months ago

Solve by splitting the middle term method
2x^2-5x+3=0​


ItzDinu: GIVEN :-
2x² - 5x + 3 = 0
TO FIND :-
Solve by splitting the middle term method
2x²-5x+3=0
SOLUTION :-

2x²-5x−3=0
We can first factorise the expression and then find the solutions.
Factorising by splitting middle term
2x²-5x−3=0
2x²-6x−1x−3=0
2x(x-3)−1(x-3)=0
(2x−1)(x-3)=0
Now we can equate the factors with zero to obtain the solutions.
2x−3=0,
x=3/2
x-1=0,
x = 1
ItzDinu: I Hope it's Helpful.

Answers

Answered by ItzDinu
8

 \huge \mathscr{\orange {\underline{\pink{\underline {Answer:-}}}}}

GIVEN :-

2x² - 5x + 3 = 0

TO FIND :-

Solve by splitting the middle term method

2x²-5x+3=0

SOLUTION :-

2x²-5x−3=0

We can first factorise the expression and then find the solutions.

Factorising by splitting middle term

2x²-5x−3=0

2x²-6x−1x−3=0

2x(x-3)−1(x-3)=0

(2x−1)(x-3)=0

Now we can equate the factors with zero to obtain the solutions.

2x−3=0,

x=3/2

x-1=0,

x = 1

  • I Hope it's Helpful.

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