solve by substituition method 2x + 7y = 11 , 3x = y + 5 for class 10
Answers
Answered by
4
2x+7(3x-5)=11
2x+21x-35=11
23x-35=11
23x=11+35
23x=46
x=2
y=3x-5
y=3×23-5
y=69-5
y=64
I am in class 7 but I hope I helped you.
if yes then mark me as brainliest
2x+21x-35=11
23x-35=11
23x=11+35
23x=46
x=2
y=3x-5
y=3×23-5
y=69-5
y=64
I am in class 7 but I hope I helped you.
if yes then mark me as brainliest
deesha12:
i found x it came 2 n y came 11
Similar questions